Answer:
65 units²
Explanation:
The polygon is composed of a trapezium and a triangle
Trapezium QRSU has area (A)
A = 0.5 h (a + b)
where h is the perpendicular height and a, b are the parallel bases.
h = RS = 7 , a = RQ = 6 and b = SU = 8, so
A = 0.5 × 7 × (6 + 8) = 0.5 × 7 × 14 = 49 units²
Triangle STU has area ( A )
A = 0.5 bh ( b is the base and h the perpendicular height )
here b = SU = 8 and h = 4 ( distance from vertex T to the base SU), so
A = 0.5 × 8 × 4 = 16 units²
Total area = 49 + 16 = 65 units²