Question

The chemical formula for ferric sulfate is Fe(SO4)3. Determine the following:

a) the number of sulfur atoms in 1.75 mole of Fe(SO4)3
b) the mass in grams of 2.65 mol of Fe(SO4)3
c) the number of moles of Fe(SO4)3 in 3.45 grams of Fe(SO4)3.
d)the mass in grams of 3 formula unit of Fe(SO4)3

Answer 1

(a) The number of sulfur atoms are,
`31.61* 10^(23)`.

(b) The mass of the mass of
`Fe_2(SO_4)_3` is, 1059.682 grams.

(c) The number of moles of
`Fe_2(SO_4)_3` is,
`8.63* 10^(-3)mole`

(d) The mass of the mass of
`Fe_2(SO_4)_3` is,
`19.95* 10^(-22)g`

Explanation :

(a) As we are given the number of moles of
`Fe_2(SO_4)_3` is, 1.75 mole. Now we have to calculate the number of sulfur atoms.

In the
`Fe_2(SO_4)_3`, there are 2 iron atoms, 3 sulfur atoms, 12 oxygen atoms.

As, 1 mole of
`Fe_2(SO_4)_3` contains
`3* 6.022* 10^(23)` number of sulfur atoms.

So, 1.75 mole of
`Fe_2(SO_4)_3` contains
`1.75* 3* 6.022* 10^(23)=31.61* 10^(23)` number of sulfur atoms.

The number of sulfur atoms are,
`31.61* 10^(23)`

(b) As we are given the number of moles of
`Fe_2(SO_4)_3` is, 2.65 mole. Now we have to calculate the mass of
`Fe_2(SO_4)_3`.

`\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3* \text{Molar mass of }Fe_2(SO_4)_3`

The molar mass of
`Fe_2(SO_4)_3` = 399.88 g/mole

`\text{Mass of }Fe_2(SO_4)_3=2.65mole* 399.88g/mole=1059.682g`

The mass of the mass of
`Fe_2(SO_4)_3` is, 1059.682 grams.

(c) As we are given the mass of
`Fe_2(SO_4)_3` is, 3.45 grams. Now we have to calculate the moles of
`Fe_2(SO_4)_3`.

`\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3* \text{Molar mass of }Fe_2(SO_4)_3`

The molar mass of
`Fe_2(SO_4)_3` = 399.88 g/mole

`3.45g=\text{Moles of }Fe_2(SO_4)_3* 399.88g/mole`

`\text{Moles of }Fe_2(SO_4)_3=8.63* 10^(-3)mole`

The number of moles of
`Fe_2(SO_4)_3` is,
`8.63* 10^(-3)mole`

(d) As we are given the formula unit of
`Fe_2(SO_4)_3` is, 3. Now we have to calculate the mass of
`Fe_2(SO_4)_3`.

As we know that 1 mole of
`Fe_2(SO_4)_3` contains
`6.022* 10^(23)` formula unit.

Formula used :

`\text{Formula unit of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3* 6.022* 10^(23)`

`3=\text{Moles of }Fe_2(SO_4)_3* 6.022* 10^(23)`

`\text{Moles of }Fe_2(SO_4)_3=4.989* 10^(-24)mole`

Now we have to calculate the mass of
`Fe_2(SO_4)_3`.

`\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3* \text{Molar mass of }Fe_2(SO_4)_3`

The molar mass of
`Fe_2(SO_4)_3` = 399.88 g/mole

`\text{Mass of }Fe_2(SO_4)_3=4.989* 10^(-24)mole* 399.88g/mole=19.95* 10^(-22)g`

The mass of the mass of
`Fe_2(SO_4)_3` is,
`19.95* 10^(-22)g`