Question

If the fugacity of a pure component at the conditions of an ideal solution is 40 bar and its mole fraction is 0.4, what is its fugacity in the solution according to the Lewis-Randall rule?

Answer 1

Answer : The fugacity in the solution is, 16 bar.

Explanation : Given,

Fugacity of a pure component = 40 bar

Mole fraction of component = 0.4

Lewis-Randall rule : It states that in an ideal solution, the fugacity of a component is directly proportional to the mole fraction of the component in the solution.

Now we have to calculate the fugacity in the solution.

Formula used :

`f_i=X_i* f_i^o`

where,

`f_i` = fugacity in the solution

`f_i^o` = fugacity of a pure component

`X_1` = mole fraction of component

Now put all the give values in the above formula, we get:

`f_i=0.4* 40\text{ bar}`

`f_i=16\text{ bar}`

Therefore, the fugacity in the solution is, 16 bar.