Answer:
The potential difference between the plates is 596.2 volts.
Step-by-step explanation:
Given that,
Capacitance

Charge

Separation of plates = 0.313 mm
We need to calculate the potential difference between the plates
Using formula of potential difference

Where, Q = charge
C = capacitance
Put the value into the formula


Hence,The potential difference between the plates is 596.2 volts.