Question

A current of 0.2 A flows through a 3 m long wire that is perpendicular to a 0.3 T magnetic field. What is the magnitude of the force on the wire in units of newtons?

Answer 1

Magnetic force, F = 0.18 N

Step-by-step explanation:

It is given that,

Current flowing in the wire, I = 0.2 A

Length of the wire, L = 3 m

Magnetic field, B = 0.3 T

It is placed perpendicular to the magnetic field. We need to find the magnitude of force on the wire. It is given by :

`F=ILB\ sin\theta`

`F=0.2\ A* 3\ m* 0.3\ T\ sin(90)`

F = 0.18 N

So, the magnitude of force on the wire is 0.18 N. Hence, this is the required solution.