Question

Calculate the electric force an electron exerts upon a proton inside a He atom if they are d=2.7⋅10^-10m apart.

Hint: Fe=k⋅qp⋅qp/d^2 where k=9⋅10^9.

A) 6.8E-8N;
B) -212.7E-9N;
C) -6.31E-9N;
D) -57.6E-10N;

Answer 1

Step-by-step explanation:

Charge of electron in He,
`q_e=1.6* 10^(-19)\ kg`

Charge of proton in He,
`q_p=1.6* 10^(-19)\ kg`

Distance between them,
`d=2.7* 10^(-10)\ m`

We need to find the electric force between them. It is given by :

`F=k(q_eq_p)/(d^2)`

`F=-9* 10^9* ((1.6* 10^(-19)\ C)^2)/((2.7* 10^(-10)\ m)^2)`

`F=-3.16* 10^(-9)\ N`

Since, there are two protons so, the force become double i.e.

`F=2* 3.16* 10^(-9)\ N`

`F=6.32* 10^(-9)\ N`

So, the correct option is (c). Hence, this is the required solution.