Answer:
The smallest integer = 49
Explanation:
It is given that, the sum of five consecutive odd integers is 265
To find the smallest integer
Let 'x' be the smallest odd integer, the other integers are,
(x + 2), (x + 4), (x + 6), and (x + 8)
x + x + 2 + x + 4 + x + 6 + x + 8 = 265
5x + 20 = 265
5x = 245
x = 245/5 = 49
Therefore the smallest integer = 49