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In a performance test, each of two cars takes 9.0 s to accelerate from rest to 28 m/s. Car A has a mass of 1379 kg, and car B has a mass of 1902 kg. Find the net average force that acts on (a) car A and (b) car B during the test.

User DDovzhenko
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1 Answer

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Step-by-step explanation:

It is given that,

Mass of car A,
m_A=1379\ kg

Mass of car B,
m_B=1902\ kg

In a performance test, each of two cars takes 9.0 s to accelerate from rest to 28 m/s. Their acceleration is given by :


a=(v-u)/(t)


a=(28\ m/s)/(9)

a = 3.12 m/s²

(a) The net force of car A,
F_A=m_Aa


F_A=1379\ kg* 3.12\ m/s^2


F_A=4302.48\ N

(b) The net force of car B,
F_B=m_Ba


F_B=1902\ kg* 3.12\ m/s^2


F_A=5934.24\ N

Hence, this is the required solution.

User Thomas Desdoits
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