Question

In a performance test, each of two cars takes 9.0 s to accelerate from rest to 28 m/s. Car A has a mass of 1379 kg, and car B has a mass of 1902 kg. Find the net average force that acts on (a) car A and (b) car B during the test.

Answer 1

Step-by-step explanation:

It is given that,

Mass of car A,
`m_A=1379\ kg`

Mass of car B,
`m_B=1902\ kg`

In a performance test, each of two cars takes 9.0 s to accelerate from rest to 28 m/s. Their acceleration is given by :

`a=(v-u)/(t)`

`a=(28\ m/s)/(9)`

a = 3.12 m/s²

(a) The net force of car A,
`F_A=m_Aa`

`F_A=1379\ kg* 3.12\ m/s^2`

`F_A=4302.48\ N`

(b) The net force of car B,
`F_B=m_Ba`

`F_B=1902\ kg* 3.12\ m/s^2`

`F_A=5934.24\ N`

Hence, this is the required solution.