Question

If the torque required to loosen a nut holding a wheel on a car is 48 N · m, what force must be exerted at the end of a 0.23 m lug wrench to loosen the nut when the angle between the force and the wrench is 41◦ ? Answer in units of N.

Answer 1

F = 318.1 N

Step-by-step explanation:

As we know that torque to open the nut is given by formula

`\tau = \vec r * \vec F`

so we can write it as

`\tau = rFsin\theta`

now we know that

`\tau = 48 Nm`

r = 0.23 m

angle between force and the wrench is 41 degree

so we have

`48 = (0.23)Fsin41`

`F = (48)/((0.23)sin41)`

`F = 318.1 N`