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Compute the diameter of a square link subjected to a compres- sive load of 27,000 lbs. Modulus of elasticity 30 x 106 psi. Proportionality limit 38,000 psi, working stress - 7000 psi, length of the link 55 in.

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Answer:

The diameter of a square link is 0.0233 inch.

Step-by-step explanation:

Given that,

Load = 27000 lbs

Modulus of elasticity
E= 30*10^(6)\ psi

Working stress
\sigma=7000\ psi

length l = 55 in

We need to calculate the diameter of a square link

Using formula of stress


\sigma=(Force)/(Area)


7000=(27000)/(\pi* d* L)

Put the value into the formula


d=(27000)/(7000*3.14*55)


d=0.0223\ inch

Hence, The diameter of a square link is 0.0233 inch.

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