A Raman line is observed at 4768.5 À, when acetylene was irradiated by 4358.3 A radiation, Calculate the equilibrium vibrational frequency that causes the shift.

Question

asked Feb 4, 2020 113k views

1 Answer

Mcritz · Answer 1 · 2020-02-09T17:07:09+0000

Answer:

The equilibrium vibrational frequency that causes the shift is
$0.56*10^(14)\ Hz$

Step-by-step explanation:

Given that,

Wavelength of Raman line
$\lambda'=4768.5\ A$

Wavelength
$\lambda=4358.3\ A$

We need to calculate the frequency

Using formula of frequency

$f =(c)/(\lambda)$

For 4748.5 A

The frequency is

f'=(3*10^(8))/(4748.5*10^(-10))

$f' =6.32*10^(14)\ Hz$

For 4358.3 A

The frequency is

f=(3*10^(8))/(4358.3*10^(-10))

$f=6.88*10^(14)\ Hz$

We need to calculate the shift

$\Delta f=f-f'$

$\Delta f=(6.88-6.32)*10^(14)\ Hz$

$\Delta f=0.56*10^(14)\ Hz$

Hence, The equilibrium vibrational frequency that causes the shift is
$0.56*10^(14)\ Hz$