Question

A Raman line is observed at 4768.5 À, when acetylene was irradiated by 4358.3 A radiation, Calculate the equilibrium vibrational frequency that causes the shift.

Answer 1

The equilibrium vibrational frequency that causes the shift is
`0.56*10^(14)\ Hz`

Step-by-step explanation:

Given that,

Wavelength of Raman line
`\lambda'=4768.5\ A`

Wavelength
`\lambda=4358.3\ A`

We need to calculate the frequency

Using formula of frequency

`f =(c)/(\lambda)`

For 4748.5 A

The frequency is

`f'=(3*10^(8))/(4748.5*10^(-10))`

`f' =6.32*10^(14)\ Hz`

For 4358.3 A

The frequency is

`f=(3*10^(8))/(4358.3*10^(-10))`

`f=6.88*10^(14)\ Hz`

We need to calculate the shift

`\Delta f=f-f'`

`\Delta f=(6.88-6.32)*10^(14)\ Hz`

`\Delta f=0.56*10^(14)\ Hz`

Hence, The equilibrium vibrational frequency that causes the shift is
`0.56*10^(14)\ Hz`