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A vector in the xy plane has a magnitude of 25 m and x component of 12 m. What is its angle with the positive x axis?

User Reichhart
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Final answer:

The angle a vector makes with the positive x-axis can be found using the cosine ratio; the angle is approximately 58.2 degrees for the vector with a magnitude of 25 m and an x-component of 12 m.

Step-by-step explanation:

To determine the angle a vector makes with the positive x-axis, we can use trigonometry since we have the magnitude of the vector and the length of the x-component. Specifically, the cosine of the angle (θ) that the vector makes with the x-axis is equal to the x-component divided by the magnitude of the vector.

Here is the formula:

cos(θ) = (x-component) / (magnitude)

By substituting the given values:

cos(θ) = 12 m / 25 m

Now calculate the angle:

θ = cos⁻¹(12/25)

θ = 58.2° (approx.)

Therefore, the vector makes an angle of approximately 58.2 degrees with the positive x-axis.

User Thach Huynh
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