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A group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. How many different combinations of 5 friends could possibly receive the tickets? A. 13 B. 40 C. 56 b. 64​
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A group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. How many different combinations of 5 friends could

possibly receive the tickets?
A. 13
B. 40
C. 56
b. 64​

User Xtian Macedo
by
8.2k points

1 Answer

4 votes


_8C_5=(8!)/(5!3!)=(6\cdot7\cdot8)/(2\cdot 3)=56

User HV Sharma
by
8.2k points
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