Question

Solve the system of equations given below.

8x + 4y = 16
7y = 15
-
1
OA. (4,-2)
B. (-2,4)
C. (1.2)
:
D.
(2,1)
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Answer 1

x = \frac{13}{14}

Explanation:

8x+4y=16

7y=15

the easiest unknown to find first is y because we have the second equation contains only y :

7y=15 we divide both sides by 7 we get : y=\frac{15}{7}

then we can substitute this value in the first equation to find x :

8x+4 \frac{15}{7} = 16

means : 8x+\frac{60}{7} = 16

8x=16-\frac{60}{7}

8x = \frac{52}{7}

divide both sides by 8 :

x = \frac{13}{14}

so the solution is (\frac{13}{14},\frac{15}{7})

Answer 2

Explanation:

we have the system :

8x+4y=16

7y=15

the easiest unknown to find first is y because we have the second equation contains only y :

7y=15 we divide both sides by 7 we get : y=
`(15)/(7)`

then we can substitute this value in the first equation to find x :

8x+4
`(15)/(7)` = 16

means : 8x+
`(60)/(7)` = 16

8x=16-
`(60)/(7)`

8x =
`(52)/(7)`

divide both sides by 8 :

x =
`(13)/(14)`

so the solution is (
`(13)/(14)`,
`(15)/(7)`)

this is the solution of the system you submitted

Now if you meant this system :

8x+4y=16

7y=15-1

we get :

7y=14 which gives us y=2

then 8x+4(2)=16 gives us : 8x+8=16

means 8x=8

means x=1

and in this case the solution will be (1,2) answer C