Question

The numerator of a fraction is 3 less than the denominator. If 1 is added to both its numerator and denominator, it becomes 2/3. Find the fraction​

Answer 1

`(x-3)/(x)` - initial fraction

`(x-3+1)/(x+1)=(2)/(3)\\\\(x-2)/(x+1)=(2)/(3)\\\\2(x+1)=3(x-2)\\2x+2=3x-6\\x=8\\\\(8-3)/(8)=(5)/(8)`

It's
`(5)/(8)`