The numerator of a fraction is 3 less than the denominator. If 1 is added to both its numerator and denominator, it becomes 2/3. Find the fraction

asked Jan 10, 2020 83.8k views

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1 vote

(x-3)/(x) - initial fraction

$(x-3+1)/(x+1)=(2)/(3)\\\\(x-2)/(x+1)=(2)/(3)\\\\2(x+1)=3(x-2)\\2x+2=3x-6\\x=8\\\\(8-3)/(8)=(5)/(8)$

It's
(5)/(8)

Jelies answered Jan 17, 2020

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