Question

What is the emf through a single coil of wire if the magnetic flux changes from -57 Wb to +43 Wb in 0.17 s? O 588 V O 344 V O 386 V O 496 V

Answer 1

Emf through a single coil of wire is 588 V.

Step-by-step explanation:

We need to find the emf through a single coil of wire if the magnetic flux changes from -57 Wb to +43 Wb in 0.17 s

According to Faraday's law, emf of coil is directly proportional to the rate of change of magnetic flux. It can be written as :

`\epsilon=(d\phi)/(dt)`

Initial flux,
`\phi_1=-57\ Wb`

Final flux,
`\phi_2=+43\ Wb`

So,
`\epsilon=(\phi_2-\phi_1)/(dt)`

`\epsilon=(43\ Wb-(-57\ Wb))/(0.17\ s)`

`\epsilon=588.23\ V`

or

`\epsilon=588\ V`

So, the EMF through a single coil of wire is 588 V. Hence, this is the required solution.