Register
What is the number of roots for polynomial function of f(x) = (x^2 + 6)^2
63.3k views
3 votes
What is the number of roots for polynomial function of f(x) = (x^2 + 6)^2

User Nihal Saxena
by
5.8k points

1 Answer

0 votes

Answer:

x=±√6i

Explanation:


(x^(2) +6)^(2) =0


x^(2)+6=0


x^(2) =-6

x=±√6i

User Crabar
by
5.7k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.6m questions

7.3m answers

Other Questions

What is the value of x? (-4) - x = 5
Can someone help me with 5??? ASAP?
1/7 + 3/14 equivalent fractions
185g in the ratio 2:3
(3x1,000,000)+(3x100,000)+(2x100) what is this number written in standard form?
Link Copied!