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What is the number of roots for polynomial function of f(x) = (x^2 + 6)^2
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What is the number of roots for polynomial function of f(x) = (x^2 + 6)^2

User Nihal Saxena
by
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1 Answer

0 votes

Answer:

x=±√6i

Explanation:


(x^(2) +6)^(2) =0


x^(2)+6=0


x^(2) =-6

x=±√6i

User Crabar
by
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