180k views
0 votes
Select the correct answer

What are the real zeros of the function g(x) = x^3 + 2x^2 - x - 2?
A. 1,-1,2
B. 1,-1, -2 c. 1,-1
D. 2, -2, 1

2 Answers

3 votes

Answer:

B. 1.-1,-2

Explanation:

just did this one

User Wissem
by
8.2k points
1 vote

Answer:

B. 1.-1,-2

Explanation:


g(x) = x ^(3) + 2 {x}^(2) - x - 2

Substitute g(x)=0


0 = {x}^(3) + 2 {x}^(2) - x - 2

Move the expression to the left


0 - {x}^(3) - 2 {x}^(2) + x + 2 = 0

Factor out -x^2 from the expression


- {x}^(2) * (x + 2) + x + 2 = 0

Factor out (x+2) from the expression


(x + 2) * ({x}^(2) + 1) = 0

When the product of the factor equals 0, at least one factor is 0


x + 2 = 0


- {x}^(2)+ 1 > = 0

Solve for x


x = - 2 \\ x = - 1\\ x = 1

User Masa Sakano
by
8.6k points

No related questions found