Question

3. How many kJ of heat are required to raise the temperature of 100.0 g of water from 25.0 c to 75.0 c? The specific heat of water is 4.184 J/g-c.

Answer 1

20.9 kJ.

Step-by-step explanation:

• We can calculate the amount of heat (Q) released to water using the relation:

Q = m.c.ΔT,

where, Q is the amount of heat released to water (Q = ??? J).

m is the mass of water (m = 100.0 g).

c is the specific heat capacity of solution (c = 4.18 J/g.°C).

ΔT is the difference in T (ΔT = final temperature - initial temperature = 75.0°C - 25.0°C = 50.0°C).

∴ Q = m.c.ΔT = (100.0 g)(4.18 J/g.°C)(50.0°C) = 20900 J = 20.9 kJ.