Answer:
Final velocity, v = 25.3 m/s
Step-by-step explanation:
Initial velocity of a locomotive, u = 19 m/s
Acceleration of the locomotive, a = 0.8 m/s²
Length of station, d = 175 m
We need to find its final velocity (v) when the nose leaves the station. It can be calculated using the third law of motion :
![v^2-u^2=2ad](https://img.qammunity.org/2020/formulas/physics/high-school/jw7t56qmbiff3sbbwkf5jokdkkf45ypqyd.png)
![v^2=2ad+u^2](https://img.qammunity.org/2020/formulas/physics/college/10ahxvol4we1an99205cs7whaymzqli88g.png)
![v^2=2* 0.8\ m/s^2* 175\ m+(19\ m/s)^2](https://img.qammunity.org/2020/formulas/physics/college/o4ubpgi23cr3v1llm6a28p7fna8mrwnjaq.png)
![v^2=(641)\ m^2](https://img.qammunity.org/2020/formulas/physics/college/gzo5w6zs0oa8piumbphss6d31s1vc0zru3.png)
v = 25.31 m/s
v = 25.3 m/s
When the nose leaves the station, it will move with a velocity of 25.3 m/s. Hence, this is the required solution.