Question

Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for opening night totaled $2071.50. The equation 10.50a+3.75b=2071.50, where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. If 82 students attended, how may adult tickets were sold?]

Answer 1

168

Explanation:

The first equation given as
`10.50a+3.75b=2071.50`

Where a is the number of adults and b is the number of students

Since, the number of students are given as 82, we can plug 82 into b and then do algebra and solve for a (shown below):

`10.50a+3.75b=2071.50\\10.50a+3.75(82)=2071.50\\10.50a+307.5=2071.50\\10.50a=2071.50-307.5\\10.50a=1764\\a=(1764)/(10.50)\\a=168`

Thus, 168 adult tickets were sold