Question

What is the exponential form of log5 9 = x?

x^9 = 5
5^x = 9
x^5 = 9
9^x = 5

Answer 1

its d 5 < x ≤ 9 .

Answer 2

B

Explanation:

Using the rule of logarithms

`log_(b)` x = n ⇔ x =
`b^(n)`

Hence

`log_(5)` 9 = x ⇒ 9 =
`5^(x)` → B