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What system of equations is shown on the graph below?

x - 2y = -4 and 2x + y =4
x - 2y = 4 and 2x + y = 4
x - 2y = -2 and 2x + y = -4
x - 2y = 2 and 2x + y =4

What system of equations is shown on the graph below? x - 2y = -4 and 2x + y =4 x-example-1
User Spiegel
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2 Answers

3 votes

The answer is B.

Hope it helps

User Brasofilo
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5 votes

Answer:

x - 2y = 4 and 2x + y = -4

Explanation:

Look at the picture.

Read the coordinates of intercepts of each line.

Put them to slope-intercept form of an equation of a line:


y=mx+b

m - slope

b - y-intercept → (0, b)

The formula of a slope:


m=(y_2-y_1)/(x_2-x_1)

The blue line:

(4, 0), (0, -2) → b= -2


m=(-2-0)/(0-4)=(-2)/(-4)=(2)/(4)=(2:2)/(4:2)=(1)/(2)

Substitute the values of a slope and an y-intercept to the equation of a line:


y=(1)/(2)x-2

Convert to the standard form
Ax+By=C:


y=(1)/(2)x-2 multiply both sides by 2


2y=x-4 subtract x from both sides


-x+2y=-4 change the signs


x-2y=4

The red line:

(-2, 0), (0, -4) → b= -4


m=(-4-0)/(0-(-2))=(-4)/(2)=-2


y=-2x-4 add 2x to both sides


2x+y=-4

What system of equations is shown on the graph below? x - 2y = -4 and 2x + y =4 x-example-1
User Heestand XYZ
by
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