Question

Calculate the molarity of the solution.

6.02 x 1022 molecules of HCI (molecular weight = 36.5 g/mole) in 2.0 liters of water
M

Answer 1

ans. is 0.05

Step-by-step explanation:

molarity=(mole of solute)/(litre of solution)

Answer 2

The molarity of the solution is 0.05
`(moles)/(L)`

Step-by-step explanation:

Molarity (M) is the number of moles of solute that are dissolved in a given volume.

Molarity is determined by the following expression:

`Molarity (M)=(number of moles of solute)/(dissolution volume)`

Molarity is expressed in units
`(moles)/(liter)`.

Then you should know the amount of moles of HCL. For that you should know that:

The Avogadro Number or Avogadro Constant is called the number of particles that constitute a substance (usually atoms or molecules) and that can be found in the amount of one mole of that substance. Its value is 6.023 * 10²³ particles per mole. Avogadro's number applies to any substance.

Therefore, applying a rule of three, 6.02*10²² molecules correspond to:

`moles=(6.02*10^(22)*1mole )/(6.023*10^(23) )`

moles=0.1 moles of HCl

Applying the definition of molarity:

`M=(0.1 moles)/(2 L)`

M= 0.05
`(moles)/(L)`

The molarity of the solution is 0.05
`(moles)/(L)`