What is the solution to this equation? x² + 101 = 1 A. 10i, -10i B. 10,-10 c. -10 D. 10i

Question

asked Nov 2, 2020 45.8k views

1 Answer

Brandon Moore · Answer 1 · 2020-11-08T09:25:58+0000

Answer:

A. 10i and -10i

Explanation:

We are given our equation as

$x^2+101=1\\$

Let us subtract 101 from both hand sides

$x^2+101-101=1-101\\$

x^2=-100

Now taking square roots on both hand sides

$\sqrt{x^(2)}} = √(-100)$

x=√(100) * √(-1)

$x=10 * (+i) \\x=10*(-i)\\$

$x=+10i \\x=-10i\\$