Question

What is the solution to this equation?

x² + 101 = 1


A. 10i, -10i
B. 10,-10
c. -10
D. 10i​

Answer 1

A. 10i and -10i

Explanation:

We are given our equation as

`x^2+101=1\\`

Let us subtract 101 from both hand sides

`x^2+101-101=1-101\\`

`x^2=-100`

Now taking square roots on both hand sides

`\sqrt{x^(2)}} = √(-100)`

`x=√(100) * √(-1)`

`x=10 * (+i) \\x=10*(-i)\\`

`x=+10i \\x=-10i\\`