Answer:
4) 0.5507 Mol Ar
5) 44.548 Mol AgNO3
6) 2.16107 Mol Li
Step-by-step explanation:
Divide = grams to mol and mol to molecules
Multiply = molecules to mol and mol to grams.
3) 22 g of Ar 1 mol 22
-------------------- * ---------------------- = ------------ (turn to decimal) = 0.5507 Mol Ar
39.948 g of Ar 39.948
4) AgNO3 = (Ag; 39.948) (N; 14.007) (O^3; 48)
39.948 + 14.007 + 48 = 101.955
7.4 x 10^23 Mc 6.02 x 10^23 Mc
---------------------- * ------------------------- = 44.548 Mol AgNO3
1 mol
5)
15g 1 Mol 15
------- * ------------------- = --------- (turn to decimal) = 2.16107 Mol Li
6.941 g of Li 6.941