Answer:
2.5 g x 1 mol/18.02 g x 6.03 kJ/mol
Step-by-step explanation:
use enthalpy of fusion for both thawing or freezing. The only difference for thawing or freezing would be that when freezing, energy is released (generated) and heat is on the product side, but when thawing , energy is consumed and it is on the reactant side. So for thawing or freezing use 6.03 kJ/mol.