Question

6. A restaurant offers a lunch special in which a customer can select from one of the 7 appetizers, one of the 10 entrees, and one of the 6 desserts. How many different lunch specials are possible?

Show your work

Answer 1

The answer is 420 lunch specials

Explanation:

10×7=70 70×6=420

Answer 2

the total different lunches is 420

Explanation:

Given that:

• Number of appetizers: 7
• Number of entrees: 10
• Number of desserts: 6

As we know that, a customer can choose 3 of the above items in their lunch and it is a combination problem.

So we have:

• P(A)The possible outcome when a customer choose appetizer : 7
• P(E)The possible outcome when a customer choose entree: 10
• P(D)The possible outcome when a customer choose desert: 6

So the total different lunches is:

P(A) *P(E)*P(D)

= 7*10*6

= 420

Hope it will find you well.