How do you find the vertex and the axis of symmetry of the equation? y = 2x^2 + 28x - 10

Question

asked Jan 18, 2020 115k views

2 Answers

Dndr · Answer 1 · 2020-01-24T12:23:24+0000

Answer:

By completing the square and rewrite equation in the form of

$y = a{(x - p)}^(2) + q$

Where the vertex is (p, q)

axis of symmetry is x=p

Explanation:

The solution is in the picture