Question

How do you find the vertex and the axis of symmetry of the equation? y = 2x^2 + 28x - 10

Answer 1

-7±3√6

Explanation:

Answer 2

By completing the square and rewrite equation in the form of

`y = a{(x - p)}^(2) + q`

Where the vertex is (p, q)

axis of symmetry is x=p

Explanation:

The solution is in the picture