Answer:
b=12 , a=6
, c=6
![√(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t462m14cxkj26cw9cmocfpgj44y1v8li5n.png)
Explanation:
based on the graph you are showing, you can use "SOH CAH TOA"
for right triangles, then you use "CAH" for get b:
![Cos(60)=(6)/(b)\\b*Cos(60)=6\\b*(1)/(2)=6\\ b=6*2\\b=12\\\\](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9t4za5bb53ydauuvttgj6yhstspbyu98wh.png)
you do the same for a, but in this case you use sin, not cos:
![sin(60)=(a)/(b) \\b*sin(60)=a\\\\12*√(3)/2=a\\ 6√(3)=a\\](https://img.qammunity.org/2020/formulas/mathematics/middle-school/erqd6lq2s73az7mh7bsw8cvmjm6pc74llg.png)
and with your b value, you can get c, but now you use Cos with the 45 angle:
![b*cos(45)=c\\12*√(2)/2=c\\ 6√(2)=c](https://img.qammunity.org/2020/formulas/mathematics/middle-school/17ux6pzfwfnq765vlcy915v0u3ef2g5rsi.png)
remember SOH CAH TOA means, Sin(x)=opposite/Hypotenuse, Cos(x)=adjacent/hypotenuse, and tan(x)=Opposite/adjacent.