Question

An electrically isolated object is electrically neutral. What is the charge on the object if you remove three electrons?

Answer 1

`+4.8\cdot 10^(-19)C`

Step-by-step explanation:

The initial charge of the object is zero, since the object is neutral:

Q = 0

When we remove three electrons, we remove a charge of:

`q' = 3 \cdot q_e`

where

`q_e = 1.6\cdot 10^(-19)C` is the charge of one electron. Substituting,

`q'=3 \cdot 1.6\cdot 10^(-19)C=-4.8\cdot 10^(-19) C`

So, the final charge on the initially neutral object will be

`q=Q-q' = 0 - (-4.8\cdot 10^(-19) C)=+4.8\cdot 10^(-19)C`