Answer:
![24√(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/69j6pk6bsxc0ivz0dkymxc648lqp8b94n6.png)
Explanation:
You need to remember that
can be written in the following for:
![a^{(1)/(n)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3te1vjr5c4cnjj1q4879dyj0208ryzl0tk.png)
Knowing this and given the expression
, you need to multiply the numbers inside the parentheses:
![(12)^{(3)/(2)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8749b96fc3gyk2a6xo7y4endkzxg0pp9wt.png)
Rewrite it in this form:
![=√(12^3)==√(1,728)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/53j0hj7txedfp5pzno06i96snc75c2nuhx.png)
Descompose 1,728 into its prime factors:
![1,728=2*2*2*2*2*2*3*3*3=2^6*3^3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/chd6m45s8zq7mpw1wztfnbbbuq5kq1o3sc.png)
Applying the Product of power property, which states that:
![(a^m)(a^n)=a^((m+n))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dq85haazi4mfq0uz6k0f50r5ielqa8p35c.png)
You can say that:
![=√(1,728)=√(2^6*3^2*3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v053zz2snx90kp6u36qpv6r4v44da3ua75.png)
Simplifying, you get:
![=2^3*3√(3)=24√(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/johyr061t8gkt6zcj67502dzqb23leyfxs.png)