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A sled of mass 8 kg slides across the ground with a friction force of 16.46 n what is μk between the sled and the ground? a. 2.1 b. 0.49 c. 0.83 d. 0.21
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A sled of mass 8 kg slides across the ground with a friction force of 16.46 n what is μk between the sled and the ground?

a. 2.1

b. 0.49

c. 0.83

d. 0.21

User Miles Elam
by
5.3k points

2 Answers

1 vote

Answer: D: .21 on apex :)

Step-by-step explanation:

User Stackflow
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3 votes

D. μk = 0.21. The coefficient of kinetic friction μk is 0.21.

The key to solve this problem is using the equation of kinetic friction force Fk = μk*n, where μk is the coefficient of kinetic friction, and N is the normal force n = m*g.

Clear μk from the equation Fk = μk*n:

μk = Fk/n

With Fk = 16.46N, and n = 8kg*9.8m/s²

μk = 16.46N/(8kg*9.8m/s²)

μk = 0.21

User JoeBrockhaus
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4.7k points
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