Question

1. Write the equation of a line in slope-intercept form that has a slope of -1/4 and passes through the point (8, -1).

2. Write the equation of a line in point-slope form that has a slope of -1 and passes through the point (-2, 5).


These are my last 2 questions thank you everyone for all the help!!

Answer 1

see explanation

Explanation:

1

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = -
`(1)/(4)`, hence

y = -
`(1)/(4)` x + c ← is the partial equation

To find c substitute (8, - 1) into the partial equation

- 1 = - 2 + c ⇒ c = - 1 + 2 = 1

y = -
`(1)/(4)` x + 1 ← in slope- intercept form

2

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = - 1 and (a, b) = (- 2, 5), hence

y - 5 = - (x - (- 2)), that is

y - 5 = - (x + 2)