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The blades in a blender rotate at a rate of 6100 rpm. When the motor is turned off during operation, the blades slow to rest in 4.1s. What is the angular acceleration as the blades slow down?

User Edmundito
by
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1 Answer

6 votes

Answer:

155.80rad/s

Step-by-step explanation:

Using the equation of motion to find the angular acceleration:


\omega_f = \omega_i + \alpha t


\omega_f is the final angular velocity in rad/s


\omega_i is the initial angular velocity in rad/s


\alpha is the angular acceleration

t is the time taken

Given the following


\omega_f = 6100rpm

Time = 4.1secs

Convert the angular velocity to rad/s

1rpm = 0.10472rad/s

6100rpm = x

x = 6100 * 0.10472

x = 638.792rad/s


\omega_f = 638.792rad/s\\

Get the angular acceleration:

Recall that:


\omega_f = \omega_i + \alpha t

638.792 = 0 + ∝(4.1)

4.1∝ = 638.792

∝ = 638.792/4.1

∝ = 155.80rad/s

Hence the angular acceleration as the blades slow down is 155.80rad/s

User Audun Kjelstrup
by
5.1k points