Question

Question Part Points Submissions Used A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from 0 to 5.30 m/s in 0.812 s. (a) What is the magnitude of the linear impulse experienced by a 62.0-kg passenger in the car during the time the car accelerates? kg · m/s (b) What is the magnitude of the average total force experienced by a 62.0-kg passenger in the car during the time the car accelerates? N

Answer 1

(a) 328.6 kg m/s

The linear impulse experienced by the passenger in the car is equal to the change in momentum of the passenger:

`I=\Delta p = m\Delta v`

where

m = 62.0 kg is the mass of the passenger

`\Delta v` is the change in velocity of the car (and the passenger), which is

`\Delta v = 5.30 m/s - 0 = 5.30 m/s`

So, the linear impulse experienced by the passenger is

`I=(62.0 kg)(5.30 m/s)=328.6 kg m/s`

(b) 404.7 N

The linear impulse experienced by the passenger is also equal to the product between the average force and the time interval:

`I=F \Delta t`

where in this case

`I=328.6 kg m/s` is the linear impulse

`\Delta t = 0.812 s` is the time during which the force is applied

Solving the equation for F, we find the magnitude of the average force experienced by the passenger:

`F=(I)/(\Delta t)=(328.6 kg m/s)/(0.812 s)=404.7 N`