Answer:
Option C
Explanation:
Two triangles are similar if they have at least 2 equal angles
Note that the HEF triangle has angles of 90 °, 60 ° and 30 °
Note that the EGF triangle has angles of 90 ° and 30 ° so the third angle must be 60 °
Then HEF and EGF are similar triangles.
By definition for similar triangles it is satisfied that if they have sides of length a, b, c and a ', b' c' then
![(a)/(a')=(b)/(b')=(c)/(c')=k](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ymudjpupo9fu1z4of4g6cmcfpz8houn22o.png)
Where the constant k is known as "scale factor"
In this case
![(HF)/(EF)=(HE)/(EG)=(FE)/(GF)=k](https://img.qammunity.org/2020/formulas/mathematics/middle-school/f3s4aieoj0u336y5hgd29nl25z5ko1py1o.png)
![k=(3)/(√(3))=(2√(3))/(2)=(√(3))/(1)=√(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3k5bxr38kfdd21febtnysc80mh24zclrqj.png)
![(FE)/(GF)=(√(3))/(1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r4bqml1210oqejds4m7x1vomjceezdcpcy.png)
or
![√(3):1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nv80rl5ferfwz5p6jxhfhx5gz5x1p8g93m.png)
The answer is Option C