Question

Write the equation in the line of point-slope form, y-y1=m(x-x1), given the slope and a point on the line:

through (8,-8) and has a slope of 3/4

Answer 1

`\bf (\stackrel{x_1}{8}~,~\stackrel{y_1}{-8})~\hspace{10em} slope = m\implies \cfrac{3}{4} \\\\\\ \begin{array}c \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-8)=\cfrac{3}{4}(x-8)\implies y+8=\cfrac{3}{4}(x-8)`