Question

Write a balanced equation for the combustion reaction that occurs between propane and oxygen.

Answer 1

`\huge \boxed{\mathrm{C_3 H_8 +5O_2 \Rightarrow 3CO_2 +4 H_2 O}}`

`\rule[225]{225}{2}`

Step-by-step explanation:

`\sf C_3 H_8 +O_2 \Rightarrow CO_2 + H_2 O`

Balancing Carbon atoms on the right side,

`\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 + H_2 O`

Balancing Hydrogen atoms on the right side,

`\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 +4 H_2 O`

Balancing Oxygen atoms on the left side,

`\sf C_3 H_8 +5O_2 \Rightarrow 3CO_2 +4 H_2 O`

`\rule[225]{225}{2}`

Answer 2

Step-by-step explanation:

The reaction between propane and oxygen is a combustion process for an hydrocarbon.

The formula of propane is given as C₃H₈ and oxygen is written as O₂

For this combustion reaction, the general equation is given as:

Cₓ
`H_(y)` + (x +
`(y)/(4)`)O₂ → xCO₂ +
`(y)/(2)`H₂O

In the reaction between propane and oxygen,

x = 3

y = 8

The reaction is then written as:

C₃H₈ + (3 +
`(8)/(4)`)O₂ → 3CO₂ +
`(8)/(2)`H₂O

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O