Question

I Need Help Pwease :->
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Answer 1

Area: 135 ft^2

Perimeter: 50 ft

Explanation:

area:

take the rectanle so length 12 x 9 = 108 so that is the length of the rectangle and now we need to find that of the triangle left over

subract 18 - 12 = 6 so that is the base of the trianle and we know the side length is 9 so plus it in A = (9)(6)/2

A = 54/2

A = 27

add 27 + 108 to get the total area

135

perimeter:

18 + 9 + 11 + 12 = 50

Answer 2

For this case we have that by definition, the perimeter of the trapezoid is given by the sum of its sides:

`p = 9 + 18 + 11 + 12\\p = 50`

So, the perimeter is 50ft

On the other hand, the area is given by:

`A = \frac {1} {2} (b_ {1} + b_ {2}) * h`

Where:

`b_ {1}:` It is the largest base

`b_ {2}:` It is the minor base

h: It's the height

Substituting the values:

`A = \frac {1} {2} (18 + 12) * 9\\A = \frac {1} {2} (30) * 9\\A = \frac {1} {2} (270)\\A = 135`

So, the area of the trapezoid is
`135 \ ft ^ 2`

Answer:

the perimeter is 50ft

the area of the trapezoid is
`135 \ ft ^ 2`