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I Need Help Pwease :->
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I Need Help Pwease :-> ******************************-example-1
User Espvar
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2 Answers

4 votes

Answer:

Area: 135 ft^2

Perimeter: 50 ft

Explanation:

area:

take the rectanle so length 12 x 9 = 108 so that is the length of the rectangle and now we need to find that of the triangle left over

subract 18 - 12 = 6 so that is the base of the trianle and we know the side length is 9 so plus it in A = (9)(6)/2

A = 54/2

A = 27

add 27 + 108 to get the total area

135

perimeter:

18 + 9 + 11 + 12 = 50

User Hustnzj
by
8.3k points
3 votes

For this case we have that by definition, the perimeter of the trapezoid is given by the sum of its sides:


p = 9 + 18 + 11 + 12\\p = 50

So, the perimeter is 50ft

On the other hand, the area is given by:


A = \frac {1} {2} (b_ {1} + b_ {2}) * h

Where:


b_ {1}: It is the largest base


b_ {2}: It is the minor base

h: It's the height

Substituting the values:


A = \frac {1} {2} (18 + 12) * 9\\A = \frac {1} {2} (30) * 9\\A = \frac {1} {2} (270)\\A = 135

So, the area of the trapezoid is
135 \ ft ^ 2

Answer:

the perimeter is 50ft

the area of the trapezoid is
135 \ ft ^ 2

User Xamgore
by
7.9k points

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