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In the United States, birth weights of newborn babies are approximately normally distributed with a mean of μ = 3,500 g and a standard deviation of σ = 500 g. What percent of babies born in the United States are classified as having a low birth weight (< 2,500 g)? Explain how you got your answer.

User Gillfish
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2 Answers

0 votes

Answer:

Sub into equation

Explanation:

User Oconn
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3 votes

Answer: 2.775%

Explanation:

Given: Mean :
\mu=3,500\ g

Standard deviation:
\sigma=500\ g

The formula to calculate z-score is given by :-


z=(x-\mu)/(\sigma)

For x= 2,500g


z=(2500-3500)/(500)=(-1000)/(500)=-2

The p-value of z = P(z<-2)=0.02275

In percent,
0.02775*100=2.775\%

The percent of babies born in the United States are classified as having a low birth weight (< 2,500 g) = 2.775%

User T C
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