A)
![3.6\cdot 10^5 J](https://img.qammunity.org/2020/formulas/physics/college/9dt0ulvy2ygrk6qusl9h15vmicweprpbby.png)
The power used by an object is defined as
![P=(E)/(t)](https://img.qammunity.org/2020/formulas/physics/high-school/3o6jk7kf8t6nvhjxdj84zyqxa41iprzfmm.png)
where
E is the energy used
t is the time elapsed
In this problem, we have
P = 100 W is the power of the light bulb
t = 1 h = 3600 s is the time elapsed
Solving for E, we find the amount of energy used by the light bulb:
![E=Pt = (100 W)(3600 s)=3.6\cdot 10^5 J](https://img.qammunity.org/2020/formulas/physics/college/i6qm522u95kgkcpqwten1lnfonyt75vpwy.png)
B)
![1.1 \cdot 10^2 m/s](https://img.qammunity.org/2020/formulas/physics/college/avsre6n9qfqe7ivjcpg4l5mz05pv9hs2v6.png)
The kinetic energy of an object is given by
![K=(1)/(2)mv^2](https://img.qammunity.org/2020/formulas/physics/middle-school/c6fs3acuplloc3whu5cpc8ui63cnl7ur39.png)
where
m is the mass
v is the speed of the object
In this problem, we have a man of mass
m = 65 kg
we want its kinetic energy to be
![E=3.6\cdot 10^5 J](https://img.qammunity.org/2020/formulas/physics/college/n3g8no9ho43du7l0k4seoo384bqcxv8t7o.png)
Therefore, we can calculate its speed from the previous formula:
![v=\sqrt{(2K)/(m)}=\sqrt{(2(3.6\cdot 10^5 J))/(65 kg)}=105.2 m/s = 1.1 \cdot 10^2 m/s](https://img.qammunity.org/2020/formulas/physics/college/mzkkddm3sn696ygeyrwcjs71uom71bxxvb.png)