Answer:
Trapezoid
Explanation:
Given quadrilateral has vertices at points A(-2,-1), B(3,13), C(15,5) and D(13,-11).
Find slopes of lines AD and BC:
![\text{Slope}_(AD)=(y_D-y_A)/(x_D-x_A)=(-11-(-1))/(13-(-2))=(-11+1)/(13+2)=(-10)/(15)=-(2)/(3)\\ \\\text{Slope}_(BC)=(y_C-y_B)/(x_C-x_B)=(5-13)/(15-3)=(-8)/(12)=-(2)/(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/qgbypbagmt6g2y1j0pcr6dpa98dlc3o32y.png)
Since the slopes are the same, lines AD and BC are parallel.
Find slopes of lines ABD and CD:
![\text{Slope}_(AB)=(y_B-y_A)/(x_B-x_A)=(13-(-1))/(3-(-2))=(14)/(5)\\ \\\text{Slope}_(CD)=(y_D-y_C)/(x_D-x_C)=(-11-5)/(13-15)=(-16)/(-2)=8](https://img.qammunity.org/2020/formulas/mathematics/high-school/qhuov4xs0az6ki5yx95pctn0d4vovdq2ou.png)
Since the slopes are different, lines AB and CD are not parallel.
This means quadrilateral ABCD is trapezoid (two opposite sides - parallel and two another opposite sides - not parallel)