Answer:
{x = 5 , y = 1 thus the Answer is B
Explanation:
Solve the following system:
{x + 5 y = 10 | (equation 1)
{3 x + y = 16 | (equation 2)
Swap equation 1 with equation 2:
{3 x + y = 16 | (equation 1)
{x + 5 y = 10 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{3 x + y = 16 | (equation 1)
{0 x+(14 y)/3 = 14/3 | (equation 2)
Multiply equation 2 by 3/14:
{3 x + y = 16 | (equation 1)
{0 x+y = 1 | (equation 2)
Subtract equation 2 from equation 1:
{3 x+0 y = 15 | (equation 1)
{0 x+y = 1 | (equation 2)
Divide equation 1 by 3:
{x+0 y = 5 | (equation 1)
{0 x+y = 1 | (equation 2)
Collect results:
Answer: {x = 5 , y = 1